Not to pick nits, but this is off by one. If you need the n most common elements, you should use c.most_common()[:-n-1:-1] because the element at c.most_

Not to pick nits, but this is off by one. If you need the n most common elements, you should use c.most_common()[:-n-1:-1] because the element at c.most_common()[-n] is actually the n-1th most common element.