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That’s because the parallelization in the STL is encapsulated. In Haskell and Rust it’s explicit, it’s not just about adding a parameter to an existing function
by jolux 6y ago
That’s because the parallelization in the STL is encapsulated. In Haskell and Rust it’s explicit, it’s not just about adding a parameter to an existing function, it’s a general mechanism.
- platinumrad 6y agoRayon literally works on iterators just like the C++ algorithm library.
- jolux 6y agoWell in that case neither of them is really comparable to what Haskell can do here. But Rust’s capabilities go far beyond Rayon as I’m sure you know.