3 ms·
It computes (2^b) % n, assuming n is an unsigned b-bit integer. You can't do this directly, since 2^b itself doesn't fit into a b-bit integer.
by edflsafoiewq 6y ago
It computes (2^b) % n, assuming n is an unsigned b-bit integer. You can't do this directly, since 2^b itself doesn't fit into a b-bit integer.