4 ms·
"Easier" as I'm using it is a metric of engineering effort more than throughput. I don't disagree - there's vastly more aggregate bandwidth available, both int
by brandmeyer 6y ago
"Easier" as I'm using it is a metric of engineering effort more than throughput. I don't disagree - there's vastly more aggregate bandwidth available, both internally and on external interfaces.
But its vastly easier to get started with CUDA or OpenCL than it is to get started with a big FPGA.
- CamperBob2 6y agoTrue, that much certainly isn't debatable.