3 ms·
For deduplicated storage you really want A=B <=> H(A)=H(B) to hold for all data you are going to see, so accessible constructions for collisions should already
by formerly_proven 6y ago
For deduplicated storage you really want A=B <=> H(A)=H(B) to hold for all data you are going to see, so accessible constructions for collisions should already bar an algorithm from this application.
- im3w1l 6y agoI 100% agree, but some people seem to go "eh it's not a problem in practice" for as long as they possibly can.