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Despite the fact that these distributions had very similar looking shapes, their products are entirely different. The distributions are shifted so that th
by appleflaxen 6y ago
Despite the fact that these distributions had very similar
looking shapes, their products are entirely different. The
distributions are shifted so that the center of one is 8
standard deviations from the center of the other
Is this last part correct?
"the distributions" means the distributions of the resulting products, correct?
I might misunderstand, but the centers of all three distributions are identical, at zero, aren't they?
- kgwgk 6y agoThis is just the setting of the example. For each of those distributions he takes two of them which don't overlap much and looks at the convolution (i.e. the distribution of the sum of two independent random variables described by them). Edit: by the way, the irony is that the convolution calculates products of probabilities and adds them!
- appleflaxen 6y agoOh! pre-combination! now I understand; thank you!