3 ms·
I don't know what you mean by "because of the physics involved". Suppose you send a 440Hz square wave, amplitude -1 to +1 V, to a speaker, and use a top-qualit
by dsr_ 6y ago
I don't know what you mean by "because of the physics involved".
Suppose you send a 440Hz square wave, amplitude -1 to +1 V, to a speaker, and use a top-quality microphone and a reasonable oscilloscope to look at the resulting wave in the air.
Here are perfectly normal things that you can expect to observe:
- the wave is no longer square
- the beginning of each cycle (attack) is louder than the middle
- the middle of the cycle is louder than the attack
- the attack and decay are both ringing with new high frequencies that you didn't send in
- integer multiples of the frequency are audible
- the sympathetic vibration of the speaker enclosure is nearly as loud as the signal
- it's very good as long as you hold the mic in exactly the right spot, but if you move it you get different distortions
- the speaker catches on fire (this excludes plasma speakers, which are supposed to be on fire when active)
All of these things are because of physics.
- dehrmann 6y agoWhat I meant is that a sine wave drives the speaker at its frequency, so I'm not sure where frequency distortions would come from. Except for moving the mic and getting a doppler effect and maybe sympathetic vibration, all of those distortions retain the fundamental frequency. To the original question, I guess all these distortions might make it harder to to distinguish between similar tones. My point was that even shitty speakers should reproduce the frequency reliably.