3 ms·
> but I don't get the "no minimal at all" argument. That's just wrong, no need to think about it. Only unbounded loss functions don't have minima, but using su
by blackbear_ 6y ago
> but I don't get the "no minimal at all" argument.
That's just wrong, no need to think about it. Only unbounded loss functions don't have minima, but using such a loss function would not make sense.
- moultano 6y agoThis isn't true. A loss function that asymptotes can also have no minima, which commonly used loss functions do.
- bananaface 6y agoDoesn't the fact the network is discrete (floats have a maximum precision) mean this isn't actually the case? There's a finite number of states the net can be in, and one (or more) is best.