3 ms·
Why are there two non-contiguous blue pieces in the Z-order curve that are contiguous in the Hilbert curve? Surely, both curves are continuous. Maybe it's that
by ogogmad 6y ago
Why are there two non-contiguous blue pieces in the Z-order curve that are contiguous in the Hilbert curve? Surely, both curves are continuous.
Maybe it's that the "slash" part of the Z isn't drawn, undermining the continuity. Or maybe the thin slash is overwritten because the curve is not injective.
- EdSchouten 6y agoExactly. The slash part isn’t drawn, which is why a Z order curve is not considered continuous.
- deleted 6y ago[deleted]
- ogogmad 6y ago> a Z order curve is not considered continuous Not true. A curve is by definition continuous, and a true Z-order curve is no exception. I was asking whether the Z-order curve displayed there was a true one. The definition of a space-filling curve is a continuous surjection from [0,1] to [0,1]^2.