In an ideal burning reaction in atmospheric air for C4H10 you get 4 CO2 and 5 H2O (and a bunch of N2) at fuel ratio of 15:1. So for 40 tons of fuel with C4H10

In an ideal burning reaction in atmospheric air for C4H10 you get 4 CO2 and 5 H2O (and a bunch of N2) at fuel ratio of 15:1. So for 40 tons of fuel with C4H10 you’ll get around 120-130 tons of CO2. Once you do the math and convert from mol for each product to KG it more or less comes out right. Hydrogen is 2 g/mol, Oxygen and Carbon are 16 and 12 respectively. So you are essentially tripling the mass simply because you are adding a heavy molecule (oxygen) to the mix.