3 ms·

For a random number m, you'd expect about 1/10 digits to be zero. Why is it surprising that 2^n would behave somewhat similarly?

• baq 16y ago
  you'd have to prove that 2^n has a uniform distribution of digits in base 10.
• qntm 16y ago
  The numbers 2^n aren't random. For example, the final digit is never 0. You might expect other patterns to appear on larger scales.