So the strategy "always choose the other door" boils down to the following simulation, which kind of makes it obvious { int count = 0; int i;

So the strategy "always choose the other door" boils down to the following simulation, which kind of makes it obvious { int count = 0; int i; for (i = 0; i < 1000; i++) { int choice1 = rand()%3; int actual = rand()%3; if (choice1 != actual) count++; }