3 ms·

(sin⁻¹(cos⁻¹(tan⁻¹(tan(cos(sin(9))))))−9)^−1 produces "Timeout. Undefined?". That's the closest I could get to baffling or tricking it. (it's division by zero

• TheDong 6y ago
  Is there a typo in that? Where's the division by zero? Wolfram alpha has that as exactly equal to 1/(3pi - 18) https://www.wolframalpha.com/input/?i=%28sin%E2%81%BB%C2%B9%28cos%E2%81%BB%C2%B9%28tan%E2%81%BB%C2%B9%28tan%28cos%28sin%289%29%29%29%29%29%29%E2%88%929%29%E2%81%BB%C2%B9 https://www.wolframalpha.com/input/?i=%28sin%E2%81%BB%C2%B9%...
  • wiml 6y ago
    It's multi-valued, I suppose. tan^-1 (tan (x)) is equal to x plus any integer multiple of pi (or of 180°). Same for the other pairs of functions. But one of the values results in a division by zero.
  • taeric 6y ago
    You did it in radians. Try degrees. Edit: (Or use 0.15708 instead of 9 in your link.)
• deleted 6y ago
  [deleted]
• agravier 6y ago
  cos is not the inverse of sin, cos(sin(9)) is not 9
  • molyss 6y ago
    I think the intended simplification is : (sin⁻¹(cos⁻¹(tan⁻¹(tan(cos(sin(9))))))−9)⁻¹ -> (sin⁻¹(cos⁻¹(cos(sin(9))))−9)⁻¹ -> (sin⁻¹(sin(9))−9)⁻¹ -> (9−9)⁻¹ -> 0⁻¹ -> 1/0
    • agravier 6y ago
      I see, right. This is curious.