4 ms·

yeah, i think i get it now. but if variables can only store functions, how would you write something like this in Copper? x = foo() bar(x.a, x.b)

• nercht12 6y ago
  x = foo() bar(x.a: x.b:) Functions can return data. So say, a=5, then to get the value of 5 out, all you have to do is call the function a. Edit: I'm assuming foo() here returns an object with members "a" and "b". An example of such a function-object would be: foo = [] { ret( [a=5, b=10] ) }
  • uryga 6y ago
    right, but doesn't that contradict this: > "in Copper, variables only store functions" because here, `x` clearly stores an object... is this about the whole "object-function" thing where Copper doesn't really distinguish the two? (btw i'm sure this is explained in the docs... but maybe this'll help folks like me who often just read the comments)
    • nercht12 6y ago
      Copper does not distinguish between function and object. An object-function has two parts: the member part and the executable body. In C++, it's analogous to: class FunctionObject { FunctionObject* members[]; void* operator() { /* executable body */ } };