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Regarding the first point: True, but the wrapper could also have been written in terms of foo.begin()/foo.end(), no? Second point: Yes, I would want the easy ca
by tom_mellior 6y ago
Regarding the first point: True, but the wrapper could also have been written in terms of foo.begin()/foo.end(), no? Second point: Yes, I would want the easy case solved. Obviously, if an algorithm cannot be wrapped like this, then I'm not asking for the impossible.
- layoutIfNeeded 6y agoNo, at least not without a separate overload for C-style arrays. If you don’t care about C arrays then yes, .begin/.end could work.