3 ms·

Yes, just slightly. It would take 133 bits. So I suppose a packet would only hold the width of the universe up to an error of maybe the width of 32 hydrogen ato

• tinus_hn 6y ago
  Also you’d need to account for the 3 to the left of the decimal point.
• neilwilson 6y ago
  The next question is what is that IPv6 address? c90f:daa2:2168:c234:c4c6:628b:80dc:1cd1 I think
• segfaultbuserr 6y ago
  There's no IPv7 beyond a proposal, but it was already fixed in IPv9 and deployed in production systems. RFC 1606 - A Historical Perspective On The Usage Of IP Version 9 https://tools.ietf.org/html/rfc1606 https://tools.ietf.org/html/rfc1606 > Whilst there are still many addresses unallocated the available space has been sharply decreased. The discovery of intelligent life on other solar systems with the parallel discovery of a faster-than-light transport stack is the main cause. This enables real time communication with them, and has made the allocation of world-size address spaces necessary, at the level 3 routing hierarchy. There is still only 1 global (spatial) level 2 galaxy wide network required for this galaxy, although the establishment of permanent space stations in deep space may start to exhaust this. This allows level 1 to be used for inter-galaxy routing. The most pressing problem now is the case of parallel universes. Of course there is the danger of assuming that there is no higher extrapolation than parallel universes...