4 ms·

I think (1..=n).rev() will do what you want? A .step_by() that accepts negative values a la python would be nice, but I can live without. I'd love a REPL for

I think (1..=n).rev() will do what you want? A .step_by() that accepts negative values a la python would be nice, but I can live without. I'd love a REPL for this sort of thing though - a website just isn't as good.

sacado2 6y ago
Thank you! I didn't know about the `=n` syntax.