3 ms·
Actually, even the definition of this form requires i, because it's e^(i)(pi/2) = i. The simple assumption that sqrt(-1) = i is problematic because you can ge
by antiform 18y ago
Actually, even the definition of this form requires i, because it's
e^(i)(pi/2) = i.
The simple assumption that sqrt(-1) = i is problematic because you can get something like
i^2 = (sqrt(-1))^2 = sqrt((-1)^2) = 1.
The wonder and surprise of complex numbers is that assuming seemingly arbitrary properties of a constant like i lead to a number of deep and beautiful results.