> if you're using the value by multiplying it with some other value, does that not imply it qualifies as normalised Certainly, "normalisation" can mean somethi

> if you're using the value by multiplying it with some other value, does that not imply it qualifies as normalised Certainly, "normalisation" can mean something more general than "rescale to the interval [0,1]". For example, "rescaling to the interval [0, 20]" might make sense in some contexts and would usually count as a type of normalisation, and would still involve muliplying by a number. But that would be multiplying by (20 / max possible value) rather than the typical case of multiplying by (1 / max possible value). So normalisation can mean something more general than the most usual common case, but it's not just any old "multiplying it with some other value". It has to specifically for the purpose of rescaling to some fixed, more useful/sensible range. > say you have a width of 500 and you want to move half way across so you have this value of 0.5 to get 250 This is a great example of multiplication that isn't normalisation! You've multiplied by 0.5 to get the midpoint, but that process isn't normalisation because you've not ended up with some more sensible range. You started with [0,infinity) (the set of all possible widths) and ended up with that same infinite range. > By dividing 250 by 500 Hang on, I'm confused about your example: are you asking about 500*0.5 (=250) or 250/500 (=0.5)? If it's the latter than that's normalisation, and not even something fancy or general but classic linear rescaling to the interval [0,1]. Yes, that's certainly normalisation. ---- Going back to my original comment: I was talking about values that were in the range 0 to 1 that hadn't reached that range by being multiplied by anything at all; they were just naturally in that range to begin with. For example, a probability would fit this bill.