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No. Letting the hardware just do its thing. Like an out of bounds memory access or divide by zero. Editing here because it looks like we've hit the max reply d
by abainbridge 6y ago
No. Letting the hardware just do its thing. Like an out of bounds memory access or divide by zero.
Editing here because it looks like we've hit the max reply depth. This wouldn't be like UB in the same way that code that could generate an out-of-bounds memory accesses is not UB. The critical thing is that the compiler should assume that the hardware error does not occur.
- chrisseaton 6y agoBut how would that be different to UB? If you let the hardware do whatever it wants that's no different to UB doing whatever it wants.
- deleted 6y ago[deleted]