4 ms·
Yes, that's almost exactly how it works. First option can be chosen to beat at least 511 others, second option to beat 255 others of the remaining, and so on. J
by ikeboy 6y ago
Yes, that's almost exactly how it works. First option can be chosen to beat at least 511 others, second option to beat 255 others of the remaining, and so on. Just add up total number of group preferences among each subset and divide by number of options to show that.
The number of people is irrelevant. This works with a million people just as well. Ignore people, only look at group pairwise preferences.