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Related unsolved mystery in ancient mathematics - the Biblical genealogy from Adam to Noah in Genesis 5 contains 10 individuals. For each of the individuals, th
by dbatten 6y ago
Related unsolved mystery in ancient mathematics - the Biblical genealogy from Adam to Noah in Genesis 5 contains 10 individuals. For each of the individuals, the genealogy reports the age at which their descendant was born, the remaining number of years in their life, and their age at death. 30 numbers in total. In the Masoretic Text (often considered the most reliable), those 30 numbers all end in a 0, 2, 5, 7, or 9. The chances of this happening by chance are effectively 0.
Possible explanations include either 1) that the numbers were corrupted, possibly when being converted from a sexagesimal system into decimal, or 2) that the author never intended the numbers to be "real" numbers in the sense we would understand them, but was instead intending to use a pattern to teach symbolic meaning. However, to my knowledge, nobody has ever offered a completely convincing interpretation of the puzzle. If #1 is correct, what were the original values and what was the process by which they were corrupted? If #2, what is the pattern that the author was constructing, and what is it intended to communicate?
Other genealogies in Genesis have similar weird features, and some have proposed theories that involve the other genealogies as well, but that's beyond the scope of this comment.
See - https://en.wikipedia.org/wiki/Genealogies_of_Genesis https://en.wikipedia.org/wiki/Genealogies_of_Genesis
- guerrilla 6y agoIt may have been for memorization or recitation purposes if the text was passed down orally before it was written down. That's the reason given by philologists of the Pali canon for some anomalous regularities and inconsistencies anyway.
- dbatten 6y agoYes, absolutely. Good point. Though one would still need to describe the pattern and how it was helpful as a memory aid... None of the proposals I've seen are simple enough that they seem useful for that purpose. But I'm admittedly from a different culture and time, so maybe what was obvious to them isn't obvious to me/us.
- pmoriarty 6y ago"those 30 numbers all end in a 0, 2, 5, 7, or 9. The chances of this happening by chance are effectively 0." What are the odds of those 30 numbers all ending in some numbers in a random set of 5 single-digit numbers? Also, considering all the numbers in the Bible, what are the odds that some arbitrarily chosen set of them will contain some sort of unusual pattern?
- guerrilla 6y agoI was thinking the same until I saw this [1] in the references of the Wikipedia article. What's with all the factors of 7? That's oddly specific. Here's [2] the article it's responding to with further tables. 1. https://www.asa3.org/ASA/PSCF/2004/PSCF6-04Johnson.pdf https://www.asa3.org/ASA/PSCF/2004/PSCF6-04Johnson.pdf 2. http://www.spachurches.com/uploads/5/6/8/7/5687389/numbers_in_genesis.pdf http://www.spachurches.com/uploads/5/6/8/7/5687389/numbers_i...
- dbatten 6y agoI don't have the math in front of me for the first question, but I've seen it worked out in the past. It's on the order of 1 in a billion. On the second question, considering "all the numbers in the Bible," an arbitrarily chosen number or set of numbers from the Bible will contain a pattern very, very often, because that's how people thought in that culture. Jesus didn't have 12 disciples by accident. They symbolically represent the 12 tribes of Israel. The genealogy in Matthew 1 doesn't contain 3 sets of 14 generations by accident. The author had to skip at least a few kings from the Jewish tradition to make it work out. And the fact that it's intentional is underscored by him explicitly saying "so, there were 3 sets of 14 generations..." (He's making a theological point, but the details of that aren't relevant to the question at hand.) I could go on... Intentional numerical patterns are, in fact, quite common! And this gives us more, not less, reason to suspect that the Genesis 5 genealogy has an intentional pattern.
- bonchicbongenre 6y agoLet's assume that final digits are uniformly distributed in such measurements (Benford's law says this isn't the case for first digits, but that's beside the point). Then P(last_digit in size 5 set) =1/2 for a single measure. So the probability they all are is 1/(2^30), which is on the order of one in a billion as the other reply says (good heuristics: 2^10 ≈ 1000, 2^20 ≈ 1,000,000, 2^30 ≈ 1,000,000,000)