>"Calcium copper titanate (also abbreviated CCTO, for calcium copper titanium oxide) is an inorganic compound with the formula CaCu3Ti4O12. It is noteworthy for

>"Calcium copper titanate (also abbreviated CCTO, for calcium copper titanium oxide) is an inorganic compound with the formula CaCu3Ti4O12. It is noteworthy for its extremely large dielectric constant (effective relative permittivity) of in excess of 10,000 at room temperature.[1]" Also: https://medium.com/starts-with-a-bang/the-last-barrier-to-ultra-miniaturized-electronics-is-broken-thanks-to-a-new-type-of-inductor-eb5c1a2c7460 https://medium.com/starts-with-a-bang/the-last-barrier-to-ul... >"The photograph shows the large grains of a practical energy-storage material, calcium-copper-titanate (CCTO), which is one of the world’s most efficient and practical ‘supercapacitors.’ The density of the CCTO ceramic is 94 percent of the maximum theoretical density." Here's a wierd idea: When we think about capacitors -- we think about the ability (of a material) to hold an electrical charge. But, what if it's not an electrical charge that the material is actually holding? What if what the material is really holding -- is the deformation of space (compression, expansion, twisting, rarefaction, pressure, ?) Or, what if the material was really holding -- was some kind of vibration or vibrations, just we can't detect them with our instruments just yet? Or maybe both of the above, just that what it is, depends on how we look at it, what we measure, how we measure it... Then, that in turn brings up the electrical field. In theory, all capacitors should have some kind of electric field surrounding them. In other words, let's suppose you had a goal to be able to measure if a capacitor was charged -- but you weren't permitted to do this by connecting a voltmeter to its leads. How else could you detect (without physically touching that circuit) if that capacitor was charged? Intuitively then, there has to be some sort of field around a capacitor, and intuitively then, this field would tell you (if you could measure it via some beam-like measuring device, rf beam, other electromagnetic beam, ?) if the capacitor was charged by measuring that field, rather than by connecting a voltmeter to the circuit. Perhaps the answer has to do with impedance (all the most tough problems in electronics/physics have to do with impedance)... Yes, all of these ideas are totally crackpot at this point! <g> Just theorizing aloud, for my future notes! <g>