3 ms·
Yes, but thats only a small part of the story, your limit only works if the numerator is constant, positive and > 0. Actually, the correct answer for lim{x->0}
by corty 6y ago
Yes, but thats only a small part of the story, your limit only works if the numerator is constant, positive and > 0. Actually, the correct answer for lim{x->0} a/x is really "anything" and "strongly depends on a and da/dx"...
So in general, assuming anything like \infty for a division by zero is wrong wrong wrong.
- BeetleB 6y agoIEEE 754 handles all the cases you mentioned - it doesn't always prescribe Inf.
- colejohnson66 6y agoSorry if I wasn’t clear. I was not implying that any a/b where b approaches 0 is always +infinity. I was simply saying that a/0 isn’t defined, but that in the case of 1/x (positive 0), it is somewhat defined as positive infinity.