Not entirely. Technical heat-death means there's no extractable work available anywhere and everything is in its most stable state for all of time. If protons

Not entirely. Technical heat-death means there's no extractable work available anywhere and everything is in its most stable state for all of time. If protons do not decay[0] (we're not sure), parent comment could be correct. That there is a distribution of protons (or something else) left which would be unique because of some 'butterfly effect'. [0] https://en.wikipedia.org/wiki/Proton_decay https://en.wikipedia.org/wiki/Proton_decay