3 ms·
I remember using Pi^2 to be approximately g (the acceleration due to gravity near the earth's surface). This comes in real handy when simplifying the time perio
by bdhe 16y ago
I remember using Pi^2 to be approximately g (the acceleration due to gravity near the earth's surface). This comes in real handy when simplifying the time period of a pendulum.
- dhimes 16y agoYep- and rounding g to 10 m/s^2 when there's no pi involved- so you can actually talk conversationally about free-fall because you can then do the math in your head.