4 ms·
In other words inertia. And while that surely winds down eventually, the same convective effect that created the movement during heating will continue while chi
by usrusr 6y ago
In other words inertia. And while that surely winds down eventually, the same convective effect that created the movement during heating will continue while chilling, sustaining it longer than one would expect.
In a typical pot, heat is added at the bottom and lost at the top (mostly through evaporation) and a bit at the sides. When heat isn't added anymore energy loss will still be mainly at the top and at the side, at least when not put on a cold surface. When suspended, e.g. on a gas stove, air convection will mage sir that the sides lose now energy than the bottom. So the direction of the convective drive remains the same in the switch from (usually more violent) heating to chilling, so it will sustain relatively well.
On the other hand, while the inertia fades the energy contained in the movement is turned into additional heat that needs to be transported say, but that's a miniscule amount of energy compared to that contained as heat: try to heat up water beyond room temperature by stirring!
- ricksunny 6y agoAh, the model you articulate here suggests that the convective currents prevalent in an (initially) hotter pot of water as it cools, is what drives the higher rate of heat energy loss as compared with a pot of water initially at a uniform temperature matching ambient. As convection does indeed exchange heat faster than conduction, then so long as the differential temperature between top and bottom continues as the pot cools, (and yes the fluid flow does trivially have fluid momentum i.e. inertia mentioned above), then there is a case that it can continhe to lose heat energy faster than the relatively still flowing, initially room temperature, pot of water.