3 ms·
No. They’re saying that it’s creating an entirely separate DOM tree unnecessarily by using shadow DOM where it isn’t needed. On a related note, I’m curious if
by jsf01 6y ago
No. They’re saying that it’s creating an entirely separate DOM tree unnecessarily by using shadow DOM where it isn’t needed.
On a related note, I’m curious if anyone has a benchmark comparing performance and memory consumption when attaching a shadow root vs not.