4 ms·
This is exactly the kind of order-of-magnitude estimation that I was looking for in the article. Where did you get the wave energy numbers?
by Zeebrommer 6y ago
This is exactly the kind of order-of-magnitude estimation that I was looking for in the article. Where did you get the wave energy numbers?
- mambru 6y agoProbably this[1] is the same boat? [1]: https://en.wikipedia.org/wiki/Hybrid_Trimaran_(Philippine_ship) https://en.wikipedia.org/wiki/Hybrid_Trimaran_(Philippine_sh...
- barbegal 6y agoI got them from this map https://commons.m.wikimedia.org/wiki/File:World_wave_energy_resource_map.png https://commons.m.wikimedia.org/wiki/File:World_wave_energy_...
- efavdb 6y agoHere's a quick estimate: The potential energy of the wave will go like mass x gravitational acceleration x height. If the depth (front to back) of the wave is about 1 meter and the height is also about 1 M, then per meter of wave we get M g h g = 10 m / s^2; M = 1 g / cm^3 = 10^6 g / m^3 = 10^3 kg / m^3; H = 1 m MGH ~ 10^4 Joules per meter If a wave comes every 10 seconds —> 10^3 joules / sec, not far from what this person quoted. We need to add to this the kinetic energy, which might double it. Playing with the other parameters we can get close to what the parent quoted.
- donaltroddyn 6y agoJust a note: at sea, when the ratio of wave height to wave length exceeds 0.17, the wave will break, so a 1m by 1m is impossibly steep.