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To be super clear, the quoted sentence continues, including the typeset formula below it. (It's an academic convention that I'm not a particular fan of.) > Pro
by Twisol 6y ago
To be super clear, the quoted sentence continues, including the typeset formula below it. (It's an academic convention that I'm not a particular fan of.)
> Product is functorial in both arguments so, in particular, we can define a functor L_a(c) = c * a.
Bartosz is saying that we can fix one side of the product, giving us a one-argument specialization that is a functor. In this case, we're fixing `a` (subscript binds tighter than parameters, in some sense) and letting `c` vary. That's what it means to be functorial in both arguments: fix either one and you get a functor.
The same phenomenon shows up in other fields where you have n-ary functions. Bilinear maps (in linear algebra) are linear in each argument. You could come up with something similar involving continuity in each argument for a binary function in real analysis (although I think that would actually be a weaker property than claiming the binary function is continuous...)
- omginternets 6y agoYup, I had gleaned that much from context. My issue is taht I don't know what a functor is! Sure, I could look it up, but my problem is that I spend all my time looking things up. At some point, this gets in the way of proper understanding. It's a strong signal that I'm missing some foundational knowledge. (Your reply is most appreciated, though!)
- Twisol 6y agoFair! Sorry for belaboring an unnecessary point ^_^;
- omginternets 6y agoNot at all!