2 ms·
We've already defined z and x by that stage, and we need y to be a unit vector perpendicular to both. So y can only be z.cross(x) (or x.cross(z) for mirrored).
by tripletao 6y ago
We've already defined z and x by that stage, and we need y to be a unit vector perpendicular to both. So y can only be z.cross(x) (or x.cross(z) for mirrored).