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Why does he take the fourth root to find the multiplier per indent? That was the only part where he lost me math-wise. I wanted to ask if RCT2 was Turing compl
by sixstringtheory 6y ago
Why does he take the fourth root to find the multiplier per indent? That was the only part where he lost me math-wise.
I wanted to ask if RCT2 was Turing complete, but looks like the same person made a video demonstrating this: https://www.youtube.com/watch?v=RQGa0DPwes0 https://www.youtube.com/watch?v=RQGa0DPwes0
Would love to see the Game of Life implemented in it!
As a fan of RCT2 in my youth, absolutely loved this. This is some of my favorite type of content to find on HN.
- deleted 6y ago[deleted]
- MarcelVos 6y agoThe multiplier of 4.11 was for a tile of length for the test mazes, which is actually 2 more tiles of maze. Every tile has 2 indents so one tile of length has 2*2=4 indents. Therefore we need to take the fourth root to go from the multiplier per tile of length to the multiplier per indent.
- sixstringtheory 6y agoThanks! Great work here :)
- evanb 6y agoMaking the maze longer by just one rule increases the number of indents by four. But, for his calculation the number of indents in the hindrance (it is valid to do it as a function of the number of tiles, instead, of you want) but the conversion rate (4:1) is in the power because it’s an exponential process.