3 ms·
Please explain the easy method for adding, for example MCMLXVII and LXV. I mean that seriously, I'm curious what the trick is.
by User23 6y ago
Please explain the easy method for adding, for example MCMLXVII and LXV. I mean that seriously, I'm curious what the trick is.
- eholk 6y agoI think originally Roman numerals didn't have shorthands like IV instead of IIII. In that case, to add Roman numerals, you just write the letters all together, sort them, and combine smaller digits into larger digits as necessary.
- jeffcoat 6y agoMCMLXVII + LXV = MCCCCCCCCCLXVII + LXV (canonicalize) = MCCCCCCCCCLXVIILXV (concatenate) = MCCCCCCCCCLLXXVVII (sort) = MCCCCCCCCCLLXXXII (combine, VV => X) = MCCCCCCCCCCXXXII (... keep combining, LL => C) = MMXXXII (... C{10} => M, nothing left to combine) = MMXXXII (optionally, look for ways to re-write with the subtraction rule)
- bluesign 6y agoI think the practical way of thinking would be: - seeing L + L = C and converting CM to M ( basically striking L L and C ) - then V + V = X, ( striking Vs and add an X) Then write whats left: MMXXXII Then try to re-write.
- philwelch 6y agoI originally thought canonicalize was an important step, but it actually isn’t for humans. For humans, CCCCCCCCC requires a lot more tedious counting than CM or even DCCCC, leading to more errors than simply allowing the human to notice that CM+C=M.
- kergonath 6y agoMCMLXVII+LXV = MCMLLXXVVII = MMXXXII Addition in Roman numerals is dead simple: you do it by just bunching symbols together. The only difficulty is subtractive notation, which wasn’t really used in Ancient Rome.
- philwelch 6y agoTokenize, concatenate, sort, reduce. MCMLXVII + LXV M CM L X V I I + L X V M CM L X V I I L X V M CM L L X X V V I I V+V=X, L+L=C, C+CM=M so MMXXXII. Convert everything to decimal if you wanna check my work. Note that converting CM to DCCCC is actually pretty unnecessary since you can just combine CM and C to make M instead of having to count up lots of C’s. A computer algorithm would be simpler by reducing CM to DCCC but adjusting for human fallibility, allowing for CM + C = M makes things a little easier. Also note that this method scales to any number of sums, not just adding two numbers together.