4 ms·
yes, I will add an inversion, it's a bijection
by debdut 6y ago
yes, I will add an inversion, it's a bijection
- jackhalford 6y agoThe space of all uuids is larger than the space of all shakespearean uuids. So by definition you can't biject them. You may be able to on able for your subset of uuids in your project, but there is less entropy when using the latter. edit: It seems the shakespearean uuids are longer than uuids so I may be conpletely wrong
- function_seven 6y agoI skimmed the code and it looks like there’s a hole for every pigeon. Space size appears to be equal.