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I think I've found a good use for continuations in a parser combinator library I'm writing, though I haven't gotten around to working on the corresponding featu

• gus_massa 6y ago
  I used to implement an equivalent of exit or return statement, like in this example. #lang racket ; implement sqrt in a very inefficient way (let/ec exit (for ([i 10]) (when (= (* i i) 49) (exit i))) "not found :(") ;==> 7 There are more idiomatic and easy ways to write this, but when you have to many nested and not nested for's, sometimes it is useful to have a magical exit-everything-now.
• a1369209993 6y ago
  You could dispute "serious", but I've used it in a not!lisp for various control flow purposes. func a0 a1 = callcc \return: # ... callcc (again =) # ... x ?? return y again again
• kazinator 6y ago
  Continuations can be implicitly used. If you have a language that is compiled using transformation to CPS. Then continuations are everywhere under the hood.