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Please, someone create 20 accounts and follow these users and publish a free 50% firehose.
by grandalf 16y ago
Please, someone create 20 accounts and follow these users and publish a free 50% firehose.
- gokhan 16y ago20K
- jerfelix 16y agoI believe you can follow 1000 people who don't follow you. So I think the Grandparent post was saying 20 accounts, each following a different 1000 people = 20K people followed, equals 50% firehose.
- djb_hackernews 16y agoThe twitter streaming api lets you track 5k users http://dev.twitter.com/pages/streaming_api http://dev.twitter.com/pages/streaming_api so you'd only need 4 users and 4 clients running on 4 AWS micro instances. But Twitter will shut you down once they find you syndicating the content.
- abraham 16y ago2000. http://support.twitter.com/articles/66885-i-can-t-follow-people-follow-limits http://support.twitter.com/articles/66885-i-can-t-follow-peo...
- jackowayed 16y agoIt would be interesting, but it wouldn't be a representative 50% sample.
- jcapote 16y agoIs there a list somewhere? this sounds like an interesting idea.
- ryanhuff 16y agoWhy bother creating the accounts when you could just use RSS. Polling every minute should be sufficient. http://twitter.com/statuses/user_timeline/259379883.rss http://twitter.com/statuses/user_timeline/259379883.rss Winning.
- djb_hackernews 16y agoTwitter won't allow that. You could use the api http://dev.twitter.com/pages/streaming_api http://dev.twitter.com/pages/streaming_api but then twitter would come after you if you tried to syndicate the content. So then you have to deal with Gnip... and thats 10 cents/1000 tweets.
- rudiger 16y agoThis isn't 50% of all tweets, it's 50% of all tweet impressions. That is, multiply each user's tweet by the number of users following them when they tweeted, and you'll find that 20K users (likely, people with more than a million followers who tweet with frequency) are half of all these impressions. However, the number of tweets you'd get by following the 20K would be far smaller than the firehose, probably a few hundredths of a percent at most.