4 ms·
Perhaps that's because C pointers are usually (always?) exactly that - a hard coded char array, which starts at memory offset 0. Depending on the circumstances
by rhn_mk1 6y ago
Perhaps that's because C pointers are usually (always?) exactly that - a hard coded char array, which starts at memory offset 0.
Depending on the circumstances, it may be easier to think about it as int array, or some other type, but the easiest on-ramp for pointers is still char[] = 0x0.