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Does anyone have a geometric intuition for Kronecker products? Or even any intuition for it? I've never been able to move beyond the formalism of it.
by 6gvONxR4sf7o 6y ago
Does anyone have a geometric intuition for Kronecker products? Or even any intuition for it? I've never been able to move beyond the formalism of it.
- enriquto 6y agoIf you think of a binary matrix as the adjacency matrix of a graph, the kronecker product corresponds to the product of graphs, which is a 100% geometrical construct. If your matrix has arbitrary weigths, this is the "weighted" graph product, where the weights of the edges are multiplied in the obvious manner (each edge in the product graph comes from a pair of edges of each input graph, and its weight is just the product of the two input weights).