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That means that if those numbers are drawn randomly from the containers, I’m asking what is the probability that a person guesses those numbers right BEFORE the

• ColinWright 6y ago
  That depends on how the person chose their numbers. So now you need to specify how the person chooses their numbers. Are they choosing their numbers uniformly at random without replacement? I still don't know that the black "mega" number has to do with this, and I'm still curious as to where the question comes from.
  • tigertheory 6y ago
    Let’s say the person chooses those numbers randomly and in the same way they are drawn (e.g. no replacement so number 1 can only be chosen once for the white balls). The black ball is there just to get the exact probability estimate for the Mega Millions lottery. To answer your question it comes from the Mega Millions lottery which draws 5 white balls and 1 black ball. And I’m curious to know what is probability I get first two numbers right.
    • ColinWright 6y ago
      OK, so the question is this: Suppose I draw 5 numbers uniformly at random from 1 to 70, and suppose I do so twice. What is the probability that the smallest two numbers match, and no others? So let a1<a2<a3<a4<a5 be the number from one draw, and let b1<b2<b3<b4<b5 be the number from the other draw. What is the probability that a1=b1, a2=b2, and a3, a4, a5, b3, b4, b5 are all different. Is that your question? How accurately do you need to know the answer? You can get an approximation quite quickly by simulation ... an exact answer will be horrible. Edit: OK, I have answers, but it would be useful to know how accurately you need your answer.
      • deleted 6y ago
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