4 ms·
Yes, exactly, I simplified it a bit for the limited space here. Basically C ~ B * SINR where B is the amount of spectrum and C is capacity. The reason mm-wave
by zw123456 6y ago
Yes, exactly, I simplified it a bit for the limited space here. Basically C ~ B * SINR where B is the amount of spectrum and C is capacity. The reason mm-wave yields such whopping throughputs is 1. space diversity, that is, each user gets a beam 2. the dedicated beam means that one site is not interfering with it's neighbor (co-channel interference) . So if you can control the RF into a tight beam, the SINR is greatly improved. So it boosts both B because not you are not sharing B you get all the B available to the carrier in your beam and SINR is greatly improved because your beam is not being interfered with by other cell sites.
You can not, unfortunately, modulate an infinite number of bits in practical implementations. The more QAM point require higher SINR to resolve. You can't have infinite SINR or Infinite Spectrum. Say you have 100Mhz of spectrum, in low band you are sharing it with others but also getting interfered by neighboring sites particularly at the cell edge.