4 ms·
I assume you're talking about the quantum resistance of the underlying schemes in use? My understanding is that all the current schemes of practical interest re
by KenoFischer 6y ago
I assume you're talking about the quantum resistance of the underlying schemes in use? My understanding is that all the current schemes of practical interest rely on the hardness of (variants of) LWE (https://en.wikipedia.org/wiki/Learning_with_errors https://en.wikipedia.org/wiki/Learning_with_errors), which is believed to be hard even if you have a quantum computer.