4 ms·
1.29 MJ/kg * 1kWh/3.6MJ = 0.3612 kWh per kg, or 361kWh per metric ton? For comparison, you get about 5 tons of CO2 produced driving 12,000 miles in an 22mpg ve
by zaroth 6y ago
1.29 MJ/kg * 1kWh/3.6MJ = 0.3612 kWh per kg, or 361kWh per metric ton?
For comparison, you get about 5 tons of CO2 produced driving 12,000 miles in an 22mpg vehicle.
361kWh * 5 = 1,805kWh, so maybe $100 of energy cost? Seems totally economical to offset the CO2 from a full year of driving.
Now what I am wondering is if there’s any reason we won’t see a typical logistics curve / cost reduction pattern like we see with most tech whether it be solar panels, battery cost, etc.
Is there a law of thermodynamics that puts a ceiling on how good this can get, and how close to the theoretical maximum are we currently?