3 ms·
I did the same thought and broke them up a little differently: 14*14 7*7*2*2 [b/c 14 = 2*7] 49*2*2 98*2 196 For whatever reason, my brain likes
by HeWhoLurksLate 6y ago
I did the same thought and broke them up a little differently:
14*14
7*7*2*2 [b/c 14 = 2*7]
49*2*2
98*2
196
For whatever reason, my brain likes using twos (and powers of it), so I play to that strong spot wherever possible.
EDIT: as noted below, I made a mistake (7·7=49,not 47,) and carried it halfway through my solution. Oops.
- iso947 6y ago7x7 isn’t 47, and 94x2 isn’t 196
- dr_zoidberg 6y agoDespite that, the breakup does hold up the correct calculation: 14 * 14 (7 * 2) * (7 * 2) 7 * 7 * 2 * 2 49 * 2 * 2 98 * 2 196 And on my side, 49 * 2 quickly resolves to "a hundred minus 2" (because 49 * 2 = (50 - 1) * 2), and pretty much the same for 196 (200 - 4).
- HeWhoLurksLate 6y agoWoops, fixed it. Thanks for noticing!
- jjoonathan 6y agoYeah, for sure, if the numbers break easily into small factors, that's the way to go. Redundant numbers still work even when the factors are few, large, or difficult to calculate, however: 17 * 17 170 + 17*7 170 + 07(49) 1(14)(49) 24(49) 289