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It takes 829 bits of binary lambda calculus to interpret BrainFuck, which is very simple programming language modeled after Turing Machines. A self-interpreter
by tromp 6y ago
It takes 829 bits of binary lambda calculus to interpret BrainFuck, which is very simple programming language modeled after Turing Machines. A self-interpreter in BrainFuck takes well over a thousand bits though [2].
Lambda calculus is not only very simple, but also very expressive. While combinatory logic, with only S and K, is even simpler than lambda calculus, and also has a trivial binary encoding (00 for S, 01 for K, and 10 for application), the shortest known self-interpreter is 263 bits, appreciably larger than for lambda calculus.
My IOCCC entry [3] has more examples of the conciseness of binary lambda calculus.
[1] https://tromp.github.io/cl/Binary_lambda_calculus.html#Brainfuck https://tromp.github.io/cl/Binary_lambda_calculus.html#Brain...
[2] https://arxiv.org/html/cs/0311032 https://arxiv.org/html/cs/0311032
[3] http://www.ioccc.org/2012/tromp/hint.html http://www.ioccc.org/2012/tromp/hint.html
- alexisread 6y agoHow does this logic compare to say Forth, APL or Joy? As far as I'm aware, they are all combinatorial languages - are they effectively implementations of SK combinators?
- kryptiskt 6y ago"The Theory of Concatenative Combinators" (http://tunes.org/~iepos/joy.html http://tunes.org/~iepos/joy.html) connects combinatorial logic with Joy.
- carapace 6y agoFWIW, I think concatenative notation is the simplest useful computational framework. ( https://joypy.osdn.io https://joypy.osdn.io disclosure: it's my project.) But I'm not mathematically sophisticated enough to make the formal argument.