4 ms·
Exactly what I was thinking. Maybe it could be formalized this way? (with t = 1 table) 1/3 * (1 table) + 1/3 * (1 table) = 2/6 * (2 tables) or 1/3 * t + 1/3
by chpmrc 6y ago
Exactly what I was thinking. Maybe it could be formalized this way? (with t = 1 table)
1/3 * (1 table) + 1/3 * (1 table) = 2/6 * (2 tables)
or
1/3 * t + 1/3 * t = 2/6 * 2 * t
but 2/6 * 2 = 2/3 so you get
1/3 * t + 1/3 * t = 2/3 * t
which is correct.