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> in a lazy language, you can certainly say: Not in haskell. Which language do you specifically have in mind?
by dependenttypes 6y ago
> in a lazy language, you can certainly say:
Not in haskell. Which language do you specifically have in mind?
- tome 6y agoYes indeed in Haskell. You have enable RecursiveDo for that particular example to work. I'm not sure why ferzul chose a recursive monadic computation when let { x = 0:y; y = 0:x } in x seems to demonstrate the same thing.