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What is the largest node/process that is currently available? Does that large size mean the lowest cost for development? I assume the trade is that fewer chips
by syedkarim 6y ago
What is the largest node/process that is currently available? Does that large size mean the lowest cost for development? I assume the trade is that fewer chips are produced from a wafer, so lower development costs are related to higher unit costs.
- zozbot234 6y ago> I assume the trade is that fewer chips are produced from a wafer Not really true once you scale down to a minimum viable size for your application, since you'll need plenty of area regardless for bonding pads, vias, interconnects etc. Nowadays the partial failure of Dennard scaling means that smaller chips may also be a lot harder to cool; it may be more advantageous to try and spread out logic in a way that might be a bit "wasteful" of area, if this makes the thermals more manageable. The real tradeoff wrt. very coarse nodes is performance.