You can get both formulas from this one: e^(0.25τ) = i but that doesn't make it a better formula. Or if it did, then the following formula would be infinit

You can get both formulas from this one: e^(0.25τ) = i but that doesn't make it a better formula. Or if it did, then the following formula would be infinitely superior to all of the above (and it doesn't directly mention either π or τ): e^(ix) = cos x + i*sin x