Correct me if I got it wrong, but does it mean that putting any Python function in any() makes it run in C??? From my understanding, the any() version is faste

Correct me if I got it wrong, but does it mean that putting any Python function in any() makes it run in C??? From my understanding, the any() version is faster is primarily because it avoids looking up .update() method each iteration. The usual Python way of optimizing such cases is: # the original slow version # 2.87753200531 sec def run(): _md5 = hashlib.md5() for i in itertools.repeat("foo", 10000000): _md5.update(i) # slight change # 1.82029104233 sec def run(): _md5 = hashlib.md5() update = _md5.update for i in itertools.repeat("foo", 10000000): update(i) # using any() # 1.50683498383 sec def run(): _md5 = hashlib.md5() any(itertools.imap(_md5.update, itertools.repeat("foo", 10000000)))