14 ms·

I don't think that is the case. Suppose a given channel (e.g. a frequency) has a maximum information per second it can carry X, this system will not allow 2X in

by hristov 16y ago

I don't think that is the case. Suppose a given channel (e.g. a frequency) has a maximum information per second it can carry X, this system will not allow 2X information to be carried. It will allow the information carrying capacity of the channel to be split, such that each side can carry a maximum amount of information A and B respectively such that A+B<=X.

83457 16y ago
"this system will not allow 2X information to be carried" I believe that is the entire point of the article. To allow double the capacity between two devices. The original capacity would be the amount of data that could be sent by a single device. However if both devices can send at the same time that is double capacity.